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1692: 图-最小生成树-Prim(不建议学生做)

金币值:2 定数:10 时间限制:1.000 s 内存限制:128 M
正确:2 提交:2 正确率:100.00% 命题人:
点赞量:0 收藏量:0 题目类型:程序 知识点: 数据结构-图

题目描述


#include "stdio.h"   
#include "stdlib.h"  
//#include "io.h" 
#include "math.h" 
#include "time.h"

#define OK 1
#define ERROR 0
#define TRUE 1
#define FALSE 0

#define MAXEDGE 20
#define MAXVEX 20
#define INFINITY 65535

typedef int Status; /* Status是函数的类型,其值是函数结果状态代码,如OK等 */

typedef struct
{
         int arc[MAXVEX][MAXVEX];
         int numVertexes, numEdges;
}MGraph;

void CreateMGraph(MGraph *G)/* 构件图 */
{
         int i, j;

         /* printf("请输入边数和顶点数:"); */

        ___________


         G->arc[0][1]=10;
         G->arc[0][5]=11;
         G->arc[1][2]=18;
         G->arc[1][8]=12;
         G->arc[1][6]=16;
         G->arc[2][8]=8;
         G->arc[2][3]=22;
         G->arc[3][8]=21;
         G->arc[3][6]=24;
         G->arc[3][7]=16;
         G->arc[3][4]=20;
         G->arc[4][7]=7;
         G->arc[4][5]=26;
         G->arc[5][6]=17;
         G->arc[6][7]=19;

         for(i = 0; i < G->numVertexes; i++)
         {
                  for(j = i; j < G->numVertexes; j++)
                  {
                           G->arc[j][i] =G->arc[i][j];
                  }
         }

}

/* Prim算法生成最小生成树  */
void MiniSpanTree_Prim(MGraph G)
{

        ________ 


}

int main(void)
{
         MGraph G;
         CreateMGraph(&G);
         MiniSpanTree_Prim(G);
 
         return 0;
 
}


输出样例    复制

(0, 1)
(0, 5)
(1, 8)
(8, 2)
(1, 6)
(6, 7)
(7, 4)
(7, 3)